Updated 2026-07-22 · 8 decks · S17 · DAS · methodology
9,9 (pair of 9s) vs dealer 7: the verdict
Basic strategy says stand. Against a dealer 7, 9,9 (pair of 9s) does best by letting the dealer take the risk of busting.
The numbers
| Action | Win | Push | Lose | EV per $1 |
|---|---|---|---|---|
| Stand | 63.1% | 13.8% | 23.1% | +0.400 |
| Split* | 53.3% | 10.0% | 36.6% | +0.370 |
| Hit | 19.6% | 1.8% | 78.7% | −0.591 |
| Double | 19.6% | 1.8% | 78.7% | −1.182 |
* win/push/lose shown per split hand; EV covers both hands per one initial bet.
Why stand is correct
A dealer showing 7 busts 26.2% of the time, and that bust chance is doing the work here: standing wins 63.1% of hands without ever risking your own bust. Drawing a card would improve the total sometimes, but the bust risk and the hands you’d ruin cost more than they gain.
For context, a dealer 7 finishes on 17–20 about 66.4% of the time, on 21 7.4%, and busts 26.2%. Those dealer outcomes are the same no matter what you hold — the whole game is choosing the action whose distribution fits them best.
What the mistake costs
Choosing split instead of stand costs about $74 per 100 such hands at $25 a hand (−0.030 EV per dollar). The genuinely expensive error here is double: −1.582 per dollar, or roughly $3955 per 100 hands at the same stakes.
Does the rule set change it?
No — stand holds across every common configuration: Vegas Strip, Atlantic City with late surrender, H17 games and European no-hole-card tables all agree here.
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9,9 against other dealer cards:
Other key hands vs a dealer 7: