Updated 2026-07-22 · 8 decks · S17 · DAS · methodology
10,10 (pair of 10s) vs dealer 6: the verdict
Basic strategy says stand. Against a dealer 6, 10,10 (pair of 10s) does best by letting the dealer take the risk of busting.
The numbers
| Action | Win | Push | Lose | EV per $1 |
|---|---|---|---|---|
| Stand | 80.1% | 10.2% | 9.7% | +0.704 |
| Split* | 61.0% | 6.8% | 32.2% | +0.576 |
| Hit | 6.9% | 0.7% | 92.3% | −0.854 |
| Double | 6.9% | 0.7% | 92.3% | −1.707 |
* win/push/lose shown per split hand; EV covers both hands per one initial bet.
Why stand is correct
A dealer showing 6 busts 42.3% of the time, and that bust chance is doing the work here: standing wins 80.1% of hands without ever risking your own bust. Drawing a card would improve the total sometimes, but the bust risk and the hands you’d ruin cost more than they gain.
For context, a dealer 6 finishes on 17–20 about 48.0% of the time, on 21 9.7%, and busts 42.3%. Those dealer outcomes are the same no matter what you hold — the whole game is choosing the action whose distribution fits them best.
What the mistake costs
Choosing split instead of stand costs about $321 per 100 such hands at $25 a hand (−0.128 EV per dollar). The genuinely expensive error here is double: −2.411 per dollar, or roughly $6028 per 100 hands at the same stakes.
Does the rule set change it?
No — stand holds across every common configuration: Vegas Strip, Atlantic City with late surrender, H17 games and European no-hole-card tables all agree here.
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10,10 against other dealer cards:
Other key hands vs a dealer 6: