Updated 2026-07-22 · 8 decks · S17 · DAS · methodology
10,10 (pair of 10s) vs dealer 10: the verdict
The verdict is stand. Against a dealer 10, 10,10 (pair of 10s) does best by letting the dealer take the risk of busting.
The numbers
| Action | Win | Push | Lose | EV per $1 |
|---|---|---|---|---|
| Stand | 59.2% | 37.1% | 3.7% | +0.555 |
| Split* | 42.7% | 17.1% | 40.2% | +0.051 |
| Hit | 7.4% | 0.3% | 92.3% | −0.849 |
| Double | 7.4% | 0.3% | 92.3% | −1.698 |
* win/push/lose shown per split hand; EV covers both hands per one initial bet.
Why stand is correct
A dealer showing 10 busts 23.0% of the time, and that bust chance is doing the work here: standing wins 59.2% of hands without ever risking your own bust. Drawing a card would improve the total sometimes, but the bust risk and the hands you’d ruin cost more than they gain.
For context, a dealer 10 finishes on 17–20 about 73.3% of the time, on 21 3.7%, and busts 23.0%. Those dealer outcomes are the same no matter what you hold — the whole game is choosing the action whose distribution fits them best.
What the mistake costs
Choosing split instead of stand costs about $1260 per 100 such hands at $25 a hand (−0.504 EV per dollar). The genuinely expensive error here is double: −2.253 per dollar, or roughly $5631 per 100 hands at the same stakes.
Does the rule set change it?
No — stand holds across every common configuration: Vegas Strip, Atlantic City with late surrender, H17 games and European no-hole-card tables all agree here.
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10,10 against other dealer cards:
Other key hands vs a dealer 10: